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Look at the manpage of awk. 'awk -f awkscript' The filename argument after the -f option is the awk script to run, not the file or files to scan. Awk reads the file(s) in the argument, or from the pipe input. That is how it works. If you need to explicitly read a lines from a file, look at 'getline()' in the gawk info file. Read a file line by line and if condition is met continue reading till end. Browse other questions tagged shell-script awk read or ask your own question. 1 year, 4 months ago. Read file line by line and remember the last position in file. Doclazy's Tech Knowledge. Solutions, Tips and HowTos for all kinds of (mostly) technology related problems that come my way. ← Choosing the field separator in awk. List Group Membership of a User → Shell Scripting: How to Read a File Line by Line in a Shell Script. Posted on September 21, 2011. Ual field from inside your awk. Using awk to extract lines in a text file. If the text file is huge, you can cheat by exiting the program on the first match. Note that this hack will not work if multiple lines are being extracted. A more interesting task is to extract every nth line from a text file. I showed previously how to do it using sed and perl.
I need to figure out how to get loop through a text file and for every line take the fields of name , project #, and email, and replace them in a email template to be sent out.
So this is the text file called send.txt:
and this is the email template called Reminder.email:
So for every line in the text file I need to replace in this email template the fields of FULLNAME: , and Project . With the corresponding values which I can do for the first line, however I cannot do it for every line.
This is my script
This is the output it produces :
As you see it did properly replace the fields but only for Jack Chen. There were 3 lines in the send.txt file so there must be 3 modified versions of the above template.
Rui F Ribeiro41.4k1616 gold badges9494 silver badges158158 bronze badges
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3 Answers
There is no reason to use
awk
for this. You could do it directly in the shell using read
. The general format is read foo bar
which will save the first field as $foo
and the rest of each line as $bar
. So, in your case, you would do something like:The
IFS
is the Input Field Separator which, when set to ,
reads comma delimited fields. This lets you take each field and store it in a variable. Note that I used two extra variables foo
and bar
. Download screensaver bergerak untuk pc matic. This is because each field needs its own variable name and you have 6 fields. If you only give 4 variable names, the 4th ($e
) will contain the fields 4 through last.Now, there are various other syntax errors in your script. First of all the shebang line is wrong, you need
terdon♦terdon#! /bin/sh
, there can't be a blank line between the #!
and the /bin/sh
. Also, in order to assign the output of a command to a variable, you need to use the var=`command`
or, preferably var=$(command)
format. Otherwise, the command itself as a string and not its output is assigned to the variable. Finally, print
is not what you think it is. You are looking for printf
or echo
. So, a better way to write your script would be:142k3434 gold badges292292 silver badges470470 bronze badges
You have used NR1 condition
terdon♦NR1{print $1}
. That means it will consider the first line of send.txt
. Use NR2 condition to get for 2nd line and so on. OR use loop to go through all the lines like,142k3434 gold badges292292 silver badges470470 bronze badges
Awk Script To Read A File Line By Lines
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Read A File In C
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Reading ls -l output line by line awk the user name and su user to run commands
Awk While Read
Using ksh on AIX what I am trying to do is to read the ls -l output from a file in a do while loop line by line. Extract the user name(3rd field) and the directory/file name(9th field) using awk and save them into variables. su -c to the user and change directory/file permisions to 777. Script I wrote is
However the problem is that it seems like that once the first awk is executed all iterations of do while are done within first awk sub shell? as it gives me all user Ids in one line (return the value in sas_user variable), output from second awk is blank as it looks like it has nothing to process? and then it tries to su all the user ids at a time and su gives error.
What I expected it to do was to awk the user Id and D/F name for first row in the ls -l output, su -c the first user to change the permisons and then go to next line of ls -l , process it the same way and keep doing it till it has read all lines from ls -l output. This is why I used a do while loop reading file line by line. If I wanted the awk to process all lines in ls -l output together I could have just piped the ls -l output to awk..
following is what I get when I run the script as root
if I run the script as non-root user then I get
s Any help would be greatly appreciated
However the problem is that it seems like that once the first awk is executed all iterations of do while are done within first awk sub shell? as it gives me all user Ids in one line (return the value in sas_user variable), output from second awk is blank as it looks like it has nothing to process? and then it tries to su all the user ids at a time and su gives error.
What I expected it to do was to awk the user Id and D/F name for first row in the ls -l output, su -c the first user to change the permisons and then go to next line of ls -l , process it the same way and keep doing it till it has read all lines from ls -l output. This is why I used a do while loop reading file line by line. If I wanted the awk to process all lines in ls -l output together I could have just piped the ls -l output to awk..
following is what I get when I run the script as root
if I run the script as non-root user then I get
s Any help would be greatly appreciated
Windows Batch Script To Read A Text File
Last edited by Scrutinizer; 11-07-2013 at 06:22 PM. Reason: code tags
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